Question

2rad3 x^2 +9rad3 + rad12 x^2 = 0​

Answer 1

Răspuns:

$x \notin \mathbb{R}$

Explicație pas cu pas:

$2\sqrt{3} \,x^2+9\sqrt{3} +\sqrt{12} \,x^2=0$

$2\sqrt{3} \,x^2+9\sqrt{3} +2\sqrt{3} \,x^2=0$

$2\sqrt{3} \, x^2+2\sqrt{3} x^2+9\sqrt{3} =0$

$4\sqrt{3} x^2+9\sqrt{3} =0\,|:\sqrt{3}$

$\implies 4x^2+9=0\implies 4x^2=-9$

$\implies x^2=-\frac{9}{4} \implies x \notin \mathbb{R}$