Question

(2radical5-3radical2)^2+(radical5+radical2)^2-(radical5-3)(radical5+3)=

Answer 1

cel mai bine e sa le facem pe bucati si pe urma sa le unim 
(2r5-3r2)^2 = 
(2r5)^2- 2 *2r5*3r2 + (3r2)^2=
20-12r10 + 18 =
38 - 12r10

(radical5+radical2)^2
r5*r5 +r2*r2 + r5*r2 =
5+2+r10=
7+r10=

(radical5-3)(radical5+3)=
(r5)^2-9=
5-9=-4

38 - 12r10 +7+r10 - (-4)  
49-2 r10