Question

(2x+1)^2-3(x+3)(x-1)=(x-2)^2+3

Answer 1

${4x}^{2} + 4x + 1 + ( - 3x - 9)(x - 1) = {x}^{2} - 4x + 4 + 3 \\ {4x}^{2} + 4x + 1 - {3x}^{2} + 3x - 9x + 9 = {x}^{2} - 4x + 7 \\ {x}^{2} - 2x + 10 = {x}^{2} - 4x + 7 \\ - 2x + 10 = - 4x + 7 \\ - 2x + 4x = 7 - 10 \\ 2x = - 3 \\ x = - \frac{3}{2}$