Question

(√2x-1)²-32x²
Va rog scrieți tot răspunsul

Answer 1

(√2x-1)²-32x² =
32=(√32)² =(4√2)²
=(√2x-1)²-(4√2x)² =
=(√2x-1-4√2x)(√2x-1+4√2x) =
=(-3√2x-1)(5√2x-1)=

Answer 2

$( \sqrt{2} x-1)^2-32x^2=( \sqrt{2} x-1)^2-4 \sqrt{2} x= \\ =(\sqrt{2} x-1-4 \sqrt{2} x)( \sqrt{2} x-1+4 \sqrt{2} x)=(-3 \sqrt{2} x-1)(5 \sqrt{2} x-1)$