Question

(2x-1)^2 <9
cum fac?

Answer 1

(2x-1)^2 <9

$-\sqrt{9}<\left(2x-1\right)$ si $\left(2x-1\right)<\sqrt{9}$

$-\sqrt{9}<\left(2x-1\right):\quad x>-1\\\left(2x-1\right)<\sqrt{9}:\quad x<2\\-1<x<2$

Answer 2

(2x-1)² < 9 <=> 2x-1∈(-3,3) <=> -3 < 2x-1 < 3 <=> -2 < 2x < 4 <=> -1 < x < 2 ,dar deoarece x∈R => x∈(-1,2) .