Question

(2x+1)la puterea a 2-a -3(x+2)la puterea a 2-a=2(7-4x)

Answer 1

4x²+4x+1-3(x²+4x+4)=14-8x
4x²+4x+1-3x²-12x-12-14+8x=0
x²-25=0
x²=25
x1=√25
x1=5
x2=-√25
x2=-5
S={-5,5}

Answer 2

$(2x+1)^{2} -3(x+2)^{2}=2(7-4x)$
$(4x^{2}+4x+1) -3(x^{2}+4x+4)=14-8x$
$(4x^{2}+4x+1) -(3x^{2}+12x+12)=14-8x$
$4x^{2}+4x+1 -3x^{2}-12x-12+8x-14=0$
$x^{2}-25=0$
$x^{2}=25$
x = +5 sau -5