Question

2x-1 supra x+1=2x supra x-1

Answer 1

$\frac{2x - 1}{x + 1} = \frac{2x}{x - 1} \\ (2x - 1)(x - 1) = 2x(x + 1) \\ 2x {}^{2} - 2x - x + 1 = 2x {}^{2} + 2x \\ 2x {}^{2} - 3x + 1 = 2x {}^{2} + 2x \\ - 3x - 2x = - 1 \\ - 5x = - 1 \\ x = \frac{1}{5}$
coroana?

Answer 2

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