Question

решите уравнение 2x^2+3x-2-0

Answer 1

Răspuns:

Explicație pas cu pas:

$2x^2+3x-2=0\\\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\x_1 = \frac{-3+\sqrt{3^2-4\cdot \:2\left(-2\right)}}{2\cdot \:2}=\frac{1}{2}\\\\x_2 = \frac{-3-\sqrt{3^2-4\cdot \:2\left(-2\right)}}{2\cdot \:2} = 2$