Question

2x^2-8 supra x^2+4x+4

3x supra x+1 + 3 supra x+1

6x+9 supra x^2-4 - x+19 supra x^2-4

Answer 1

(2x²-8)/(x²+4x+4)=
2(x-2)/(x+2)=0
(x-2)/(x+2)=0
x-2=0
x=2

3x/(x+1)+3/(x+1)=(3x+3)/(x+1)=3*(x+1)/(x+1)=3
x=3

(6x+9)/(x²-4-x+19)/(x²-4)
(6x+9)/[(x²-4)(x²-x+15)]=0
6x+9=0
3(2x+3)=0
2x+3=0
2x=-3
x=-3/2