Question

2x(√3-1)+√3+√3(2x-1)=2√3(4-x√3)+2(5+x)
Va rog rezolvare

Answer 1

2x(√3-1)+√3+√3(2x-1)=2√3(4-x√3)+2(5+x) = 2x√3-2x +√3 +2x√3 -√3 = 8√3 -6x+10-2x
4x √3 -2x = 8√3 -4x+10
4x√3-2x+4x = 8√3 +10
4x√3+2x= 8√3 +10
(4√3+2)x = 8√3 +10 | :(4√3+2)
x= 19+6√3 /11
Se reduc termeni opusi √3 si -√3

Answer 2

2V3x-2x+V3+2V3x-V3=8V3-6x+10+2x
4V3x-2x=8V3-4x+10
4V3x-2x+4x=8V3+10
4V3x+2x=8V3+10
2x(2V3+1)=8V3+10
2x=(8V3+10)/(2V3+1) rationalizam cu 2V3-1 
2x=(8V3+10)(2V3-1) supra (12-1)
2x=(48-8V3+20V3-10)/11
2x=(38+12V3)/11
x=(38+12V3)/11 ori 1/2 
x= (38+12V3)/22 
x=2(19+6V3)/22
x=(19+6V3)/11