Question

(2x-3)^2+(2x+3)^2=(2 radical 2 x -3)(2 radical 2 x +3)+x-1. Va rog !!! Repede!!

Answer 1

(2x-3)²+(2x+3)² = (2√2x-3)(2√2x+3)+x-1
4x²-12x+9+4x²+12x+9 = 8x²-9+x-1
8x²+18 = 8x²-10+x
8x²+18-8x²+10+x = 0
x+18 = 0
x = -18.



J'espère aidé :)