Question

(2x-3)^2-(2x-3)(3x+2)^2=?

Answer 1

${(2x - 3)}^{2} - (2x - 3) {(3x + 2)}^{2}$

$= {(2x - 3)}^{2} - (2x - 3)(9 {x}^{2} + 12x + 4)$

$= (2x - 3)(2x - 3 - 9 {x}^{2} - 12x - 4)$

$= (2x - 3)( - 9 {x}^{2} - 10x - 7)$

$= - 18 {x}^{3} - 20 {x}^{2} - 14x + 27 {x}^{2} + 30x + 21$

$= - 18 {x}^{3} + 7 {x}^{2} + 16x + 21$