Question

(2x-3)^2=; (3x+2)^2=;(2x-3)•(2x+3)=; ​

Answer 1

1. .......= (2x)² - 2·2x·3 + 3² = 4x² - 12x + 9

2. ......= (3x)² + 2·3x·2 + 2² = 9x² + 12x + 4

3. .......= (2x)² - 3² = 4x² - 9

sper ca am ajutat!

Answer 2

Răspuns:

Explicație pas cu pas:

( 2 x - 3)² = ( 2 x)² - 2 × 2 x × 3 + 3² = 4 x² - 12 x + 9

( 3 x + 2 )² = ( 3 x )² + 2 × 3 x × 2 + 2² = 9 x² + 12 x + 4

( 2 x - 3 ) ( 2 x + 3 ) = 4 x² - 6 x + 6 x - 9 = 4 x² - 9