Question

(2x-3)×(2x^2-1)+(2x^2-8)×(2x-3)=?

Answer 1

Explicație pas cu pas:

$(2x - 3) \times (2x {}^{2} - 1) + (2x {}^{2} - 8) \times (2 x - 3) \\ factor \: comun \: (2 x - 3) \\ (2x - 3)(2x {}^{2} - 1 + 2x {}^{2} - 8) = \\ (2x - 3)(4x {}^{2} - 9) = \\ (2x - 3)((2x) {}^{2} - 3 {}^{2} ) = \\ (2x - 3)(2x - 3)(2x + 3) = \\ (2x - 3) {}^{2} (2x + 3)$