Question

2x^3+2x^2-3x-1=0 cum se rezolva

Answer 1

X^3+x^3+2x^2-3x-1=x (x^2+2x-3)+ x^3-1=x(x^2+ 3x-x-3)+ (x-1)(x^2+x+1)=x (x (x+3)-(x+3))+(x-1)(x^2+x+1)=x×(x+3)(x-1)+(x-1)(x^2+x+1)= fac comun pe x-1 (X-1)(x^2+3x+x^2+x+1)=(x-1)(2 x^2+4x +1) =0 X=1 Sau 2x^2+4x+1=0 Calculam delta D=16-8=8 X1,2=-4+sau - 2 radical din 2 totul supra4 X1=(-2+rad 2)/2 X2=(-2-rad 2)/2