Question

2x+3 itregi 5 pe 6 = 7 intregi 1 pe 9
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Answer 1

$2x+3 \frac{5}{6}=7 \frac{1}{9} \\ 2x+ \frac{23}{6} = \frac{64}{9} | * 54 \\ 2x*54+54* \frac{23}{6} =54* \frac{64}{9} \\ 108x+207=384 \\ 108x=384-207 \\ 108x=177 \\ x= \frac{177}{108} \\ x=1 \frac{69}{108}$
S={1 intreg 69/108}