Question

2x+3 supra 9 -2/3 ori (x+2)= 2x-5 supra 18 + x/6

Answer 1

[tex]\frac{2x+3}{9}-\frac{2}{3}\cdot(x+2)=\frac{2x-5}{18}+\frac{x}{6}|\cdot 18\\ 2(2x+3)-12(x+2)=2x-5+3x\\ 4x+6-12x-24=5x-5\\ -18-8x=5x-5\\ -3x=13\\ x=-\frac{13}{3} [/tex]