Question

2x+3supra3-2x-1supra
6=x+2/2

Answer 1

(2x+3)/3 - (2x-1)/6 = (x+2)/2

2(2x+3)/6 - (2x-1)/6 = 3(x+2)/6

4x+6 - 2x+1 = 3x+6

2x+7=3x+6

-x+7=6

-x=-1

x=1

Answer 2

$\frac{(2x + 3)}{3} - \frac{(2x - 1)}{6} = \frac{(x + 2)}{2} \ \\ \frac{2(2x + 3)}{6} - \frac{(2x - 1)}{6} = \frac{3(x + 2)}{6} \\ 4x + 6 - 2x + 1 = 3x + 6 \\ 2x + 7 = 3x + 6 \\ - x + 7 = 6 \\ - x = - 1 \\ x = 1$