Question

[2x-5]=7
[3-x supra 2]= - 4
[x-5 supra 7 ]= x
[2x-5 supra 3 ] =x+1
[2+x-1 supra 3 (x-1 supra 3)]=2x-2
[1 supra 2 + x supra 3 ] =2-x

Answer 1

1)

$2x-5=7$

$2x=7+5$

$2x=12$

$x=\frac{12}{2}$

$x=6$

2)

$\frac{3-x}{2}=-4$

$\frac{2\left(3-x\right)}{2}=2\left(-4\right)$

$3-x=-8$

$-x=-11$

$x=11$

3)

$\frac{x-5}{7}=x$

$x-5=7x$

$x=7x+5$

$x-7x=5$

$-6x=5$

$x=-\frac{5}{6}$

4)

$\frac{2x-5}{3}=x+1$

$2x-5=3x+3$

$2x=3x+8$

$2x-3x=8$

$-x=8$

$x=-8$

5) imi pare rau, dar nu inteleg forma ecuatiei si nu vreau sa rezolv dupa un algoritm incorect, astept putin mai explicit in comentarii cum ar trebuie sa fie forma fractiei si o sa o rezolv))

6)

$\frac{1}{2}+\frac{x}{3}=2-x$

$\frac{x}{3}=-x+\frac{3}{2}$

$\frac{x}{3}\cdot \:6=-x\cdot \:6+\frac{3}{2}\cdot \:6$

$2x=-6x+9$

$2x+6x=9$

$8x=9$

$x=\frac{9}{8}$