Question

2x*+5x-3=0 Rezolvare

Answer 1

${2x}^{2} + 5x - 3 = 0$

$a = 2$

$b = 5$

$c = - 3$

$\Delta = {b}^{2} - 4ac$

$\Delta = {5}^{2} - 4 \times 2 \times ( - 3)$

$\Delta = 25 + 24$

$\Delta = 49$

$x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2a}$

$x_{1,2}=\frac{-5\pm\sqrt{49}}{2 \times 2}$

$x_{1,2}=\frac{-5\pm7}{4}$

$x_{1}=\frac{-5 + 7}{4}$

$x_{1}=\frac{2}{4}$

$x_{1}=\frac{1}{2}$

$x_{2}=\frac{-5 - 7}{4}$

$x_{2}= - \frac{12}{4}$

$x_{2}= - 3$