Question

2x²-5x+3=0 $3x^{2} -7x+4=0$

Answer 1

Explicație pas cu pas:

$2x^{2}-5x+3=0$

$\Delta = 25 - 24 = 1 \iff x_{1;2} = \dfrac{5 \pm 1}{4}$

$x_{1} = \dfrac{5 - 1}{4} = 1$

$x_{2} = \dfrac{5 + 1}{4} = \dfrac{3}{2}$

$\implies \bf S = \Big\{1 ; \dfrac{3}{2} \Big\}$

.

$3x^{2} -7x+4=0$

$\Delta = 49-48 = 1 \iff x_{1;2} = \dfrac{7 \pm 1}{6}$

$x_{1} = \dfrac{7 - 1}{6} = 1$

$x_{2} = \dfrac{7 + 1}{6} = \dfrac{4}{3}$

$\implies \bf S = \Big\{1 ; \dfrac{4}{3} \Big\}$