Question

2x²+x-1 supra 2x²+3x+1

Answer 1

simplificarea in atasament

Answer 2

$\it\dfrac{2x^2+x-1}{2x^2+3x+1}=\dfrac{2x^2+2x-x-1}{2x^2+2x+x+1}=\dfrac{2x(x+1)-(x+1)}{2x(x+1)+(x+1)} =\dfrac{(x+1)(2x-1)}{(x+1)(2x+1)}=\\ \\ \\ =\dfrac{2x-1}{2x+1}$