Question

(2X3+5xi)-3x2=4x5; Alternita: i,a!
ax4-15=(80-75)x5;


(6x4-ix3)+9x4=3x10+3x3;
96-(8x4+ax3)=5x6+19


96-(9x5-9xi)=5x6+57;
96-(5x5+ax6-40)x2=9x10.

Answer 1

(2X3+5xi)-3x2=4x5
(6+5xi)-6=20
6+5xi=20+6
6+5×i=26
5×i=26-6
5×i=20
i=20:5
i=4


ax4-15=(80-75)x5
ax4-15=5x5
ax4-15=25
a×4=25+15
a×4=40
a=40:4
a=10

(6x4-ix3)+9x4=3x10+3x3
(24-ix3)+36=30+9
(24-ix3)+36=39
24-ix3=39-36
24-ix3=3
i×3=24-3
i×3=21
i=21:3
i=7


96-(8x4+ax3)=5x6+19
96-(32+ax3)=30+19
96-(32+ax3)=49
32+ax3=96-49
32+ax3=47
a×3=47-32
a×3=15
a=15:3
a=5

96-(9x5-9xi)=5x6+57
96-(45-9xi)=30+57
96-(45-9xi)=87
45-9xi=96-87
45-9xi=9
9×i=45-9
9×i=36
i=36:9
i=4


96-(5x5+ax6-40)x2=9x10
96-(25+ax6-40)x2=90
(25+ax6-40)×2=96-90
(25+ax6-40)×2=6
25+ax6-40=6:2
25+a×6-40=3
25+ax6=3+40
25+a×6=43
a×6=43-25
a×6=18
a=18:6
a=3


Dacă tu crezi că merit, astept coroana!