Question

2x3 la puterea 2-3 la puterea 2+3x[3+3x(3 la puterea 3-3 la puterea 5: 3 la puterea 3-3 la puterea 2)]=?

Answer 1

2x3^2-3^2+3[3+3(3^3-3^5:3^3-3^2)]=
=2x9-9+3[3+3(3^3-3^2-3^2)]=
=18-9+3[3+3(27-9-9)]=
=9+3[3+3(18-9)]=
=9+3(3+3x9)=
=9+3(3+27)=
=9+3x30=
=9+90=99

Answer 2

2·3² - 3²+ 3·[3+3·(3³- 3⁵: 3³- 3²)] =

2·3² - 3²+ 3·{3+3·[3²(3- 1- 1)]}=

2·3² - 3²+ 3·(3+3·3²1)=

2·3² - 3²+ 3·[3(1+3²)]=

2·3² - 3²+ 3·[3(1+9)]=

2·3² - 3²+ 3·(3·10)=

2·3² - 3²+ 3·30=

3²(2· - 1)+ 3·30=

3²·1+ 3·30=

3²+ 3·30=

9+ 3·30=

9+ 90=

99