Question

3 033+2x{6-3x [(19-3x x):2]}:8-1 033=2000 ​

Answer 1

metoda "mersului invers":

$3 033 + 2 \times \{6 - 3 \times [(19 - 3 \times x):2] \}:8 - 1 033 = 2000$

$3 033 + 2 \times \{6 - 3 \times [(19 - 3 \times x):2] \}:8 = 2000 + 1033$

$3 033 + 2 \times \{6 - 3 \times [(19 - 3 \times x):2] \}:8 = 3033$

$2 \times \{6 - 3 \times [(19 - 3 \times x):2] \}:8 = 3033 - 3033$

$2 \times \{6 - 3 \times [(19 - 3 \times x):2] \}:8 = 0$

$2 \times \{6 - 3 \times [(19 - 3 \times x):2] \} = 0 \times 8$

$2 \times \{6 - 3 \times [(19 - 3 \times x):2] \} = 0$

$6 - 3 \times [(19 - 3 \times x):2] = 0 \div 2$

$6 - 3 \times [(19 - 3 \times x):2] = 0$

$3 \times [(19 - 3 \times x):2] = 6$

$(19 - 3 \times x):2 = 6 \div 3$

$(19 - 3 \times x):2 = 2$

$19 - 3 \times x = 2 \times 2$

$19 - 3 \times x = 4$

$3 \times x = 19 - 4$

$3 \times x = 15$

$x = 15 \div 3$

$\implies \bf x = 5$