Question

3(1-x)^2-4(x-2)^2+5(x-3)^2=(2x-3)^2+4-x ma ajuta cineva,va rog. trebuie x=19/7

Answer 1

3(1-2x+x ²)-4(x²-4x+4)+5(x²-6x+9)=4x²-12x+9+4-x
3-6x+3x²-4x²+16x-16+5x²-30x+45=4x²-13x+13
4x²-20x+32=4x²-13x+13
-20x+32=-13x+13
-20x+13x=13-32
-7x=-19
x=19/7