Question

(3•15^12+2•15^12):15^11+(3^2+3^2):(3^3+3^3):3+1^2005-2005^0=?
Va rog, e urgent!
Dau coroana!

Answer 1

15^12(3+2)÷15^11+18÷54÷3+1-1=15×5+1=75+1=76

Answer 2

Răspuns:

Explicație pas cu pas:

( 3 x 15¹² + 2 x 15¹² ) : 15¹¹+ (3²+ 3² ) : ( 3³ + 3³) : 3 +1²⁰⁰⁵ - 2005⁰

= 15¹² x ( 3 + 2 ) : 15¹¹ + 3² x ( 1 + 1 ) : [3³ x ( 1 + 1 ) ]: 3+ 1 - 1 =

= 15⁽¹²⁻¹¹⁾ x 5 + 3² x 2 : (3³ x 2 ) : 3 + 0 =

= 15¹ x 5 + 18 : 54 : 3 =

= 75 + 1/9 =

= 675/9 + 1/9 =

= 676/9 =

= 75,(1)

Daca in exercitiu era o paranteza dreapta atunci rezultatul este:

( 3 x 15¹² + 2 x 15¹² ) : 15¹¹+ (3²+ 3² ) : [( 3³ + 3³) : 3] +1²⁰⁰⁵ - 2005⁰=

= 15¹² x ( 3 + 2 ) : 15¹¹ + (9+9) : [ ( 27 + 27 ) : 3 ]+ 1 - 1 =

=  15 x 5 + 18 : ( 54 : 3 ) + 0 =

= 75 + 18 : 18 =

= 75 + 1 =

= 76