Question

3^2-2^48:(2^4×2^11)^3+1^2017+(2^2×3^2):(2×3) ( Calculați )

Answer 1

3^2-2^48:(2^15)^3+1+2^1×3^1
3^2-2^48:2^45+7
3^2-2^3+7
9-8+7
8

Answer 2

$3^{2}-2^{48}:(2^{4+11)})^{3}+1+\frac{(2^{2} \cdot3^{2})}{2\cdot3}\\ \\ 3^{2}-2^{48}:( 2^{15\cdot3} )+1+2\cdot3= \\ \\9- 2^{48}:2^{45}+7= \\ \\ 9- 2^{48-45} +7= \\ \\ 9-8+7= \\ \\ 3^{2}-2^{48}:(2^{4+11)})^{3}+1+\frac{(2^{2} \cdot3^{2})}{2\cdot3}=8$