Question

[(3*2+3*4):(23-20)+4*3+2]*2-25

acolada 1+2*[3+4*(5*6+7)] inchidem acolada :3 -100

1+2+3+....................+73=..

336:(7 la puterea a doua +0 la a 7-5 la a 2

Answer 1

[(3·2+3·4):(23-20)+4·3+2]·2-25=[(6+12):3+12+2]·2-25=
(18:3+14)·2-25=
(6+14)·2-25=
20·2-25=40-25=15

{1+2·[3+4·(5·6+7)] } :3 -100=
{1+2·[3+4·(30+7)]}:3-100=
{1+2·[3+4·37]}:3-100=
{1+2·[3+148]}:3-100=
{1+2·151}:3-100=
{1+302}:3-100=
303:3-100=101-100=1

S=1+2+3+....................+73
S=73+72+..................+3+2+1
S+S=74+74+...+74
2·S=74·73
S=(74·73)/2=2701

336:(7²+0⁷-5²)=
336:(59-25)=
336:34=334/34=simplificam=167/17