Question

√3(2√3+6x)-√108(x-√3)+3√3(2√3x-√3)

Answer 1

6+$6\sqrt{3}x- \sqrt{108}x+18+18x-9=6 \sqrt{3}x- \sqrt{108} x+18x+9=$
$6 \sqrt{3}x-6 \sqrt{3}x+18x+9=$ 18x+9=0 ⇒ 18x= -9 ⇒ x = $\frac{-9}{18}$ ⇒ x = $\frac{-1}{2}$