Question

[(3^2)^5:3^7-3^0-3^2]*4:34+2^2​

Answer 1

$[(3^2)^5:3^7-3^0-3^2]*4:34+2^2=\\(3^{10}:3^7-3^0-3^2)*4:34+2^2=\\(3^3-1-9)*4:34+2^2=\\(27-1-9)*4:34+4=\\17*4:34+4\\68:34+4=\\2+4=6$

Answer 2

Răspuns:

Explicație pas cu pas: