Question

(√3+√2)•(5-√6)+(√2-1)²-3√3

Answer 1

(√3+√2)(5-√6)+(√2-1)²-3√3=5√3-√18+5√2-√12+2-2√2+1-3√3=5√3-√9*2+5√2-√4*3+2-2√2+1-3√3=5√3-3√2+5√2-2√3+2-2√2+1-3√3=3
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Answer 2

$( \sqrt{3} + \sqrt{2} )(5- \sqrt{6} )+( \sqrt{2} -1)^2-3 \sqrt{3} = \\ =5 \sqrt{3} - \sqrt{18} +5 \sqrt{2} - \sqrt{12} +( \sqrt{2} )^2-2 \cdot \sqrt{2} \cdot 1+1^2-3 \sqrt{3} = \\ =5 \sqrt{3} -3 \sqrt{2} +5 \sqrt{2} -2 \sqrt{3} +2-2 \sqrt{2} +1-3 \sqrt{3} =2+1=3$