Question

(√3+√2-√6)•√6
va rog

Answer 1

$( \sqrt{3} + \sqrt{2} - \sqrt{6}) \times \sqrt{6} = \\ \\ \sqrt{6} \sqrt{3} + \sqrt{6} \sqrt{2} + \sqrt{6} \times - \sqrt{6} = \\ \\ \sqrt{18} + \sqrt{12} + \sqrt{6} \times - \sqrt{6} = \\ \\ 3 \sqrt{2} + 2 \sqrt{3} + \sqrt{6} \times - \sqrt{6} = \\ \\ 3 \sqrt{2} + 2 \sqrt{3} - \sqrt{6} \sqrt{6} = \\ \\ 3 \sqrt{2} + 2 \sqrt{3} - \sqrt{36} = \\ \\ 3 \sqrt{2} + 2 \sqrt{3} - 6$