Question

3(2+radical din3)(2-radoical di 3)+(2-radical din 3) la puterea a 2=
ajutatima va rog

Answer 1

3(2+√3)(2-√3)+(2-√3)°. (°-inseamana la puterea a doua ) = 3x2°-(√3)°+2°-(√3)°= 3x4-3+4-3=12-3+4-3=9+1=10