Question

3(2+radical2)-3radical2=6

Answer 1

$3(2 + \sqrt{2} ) - 3 \sqrt{2} = 6$

$3 \times 2 + 3 \times \sqrt{2} - 3 \sqrt{2} = 6$

$6 + 3 \sqrt{2} - 3 \sqrt{2} = 6$

$6 + 0 = 6$

$6 = 6 \: A$

Answer 2

3(2+√2) - 3√2 = 6 

3(2+√2)-3√2 = 6

= 6 + 3√2 - 3√2 = 6

6 = 6 ( adevarat )