Question

|(3-2radical din 2)la patrat|-|(radical din 2 inmultit(8-12,44)|+|radical din 2-5 asupra 2-3,(6)

Answer 1

[tex]| (3-2 \sqrt{2} )^{2} |-| \sqrt{2} (8-12.44)|+| \frac{ \sqrt{2}-5 }{2-3.(6)} |=\\= (3-2 \sqrt{2} )^{2} -| \sqrt{2} *(-4.44)|+\frac{ \sqrt{2}-5 }{2-3.(6)}=\\= (9+4 *2-12\sqrt{2} ) -\sqrt{2} *4.44+\frac{ \sqrt{2}-5 }{2- \frac{3*6+6}{9} }=\\= 9+8-12\sqrt{2} -\sqrt{2} *4.44+\frac{ \sqrt{2}-5 }{ \frac{6}{3} - \frac{8}{3} }=\\= 17 -\sqrt{2} *(4.44+12)+\frac{ -(5-\sqrt{2} )}{- \frac{2}{3} }=\\= 17 -\sqrt{2} *16.44+\frac{ 5-\sqrt{2} }{\frac{2}{3} }=\\= 17 -\sqrt{2} *16.44+\frac{ 3*(5-\sqrt{2}) }{2 }=\\=[/tex]
[tex]\frac{34}{2} -\frac{ \sqrt{2} *32.88}{2}+\frac{ 3*(5-\sqrt{2}) }{2 }=\\= \frac{34- \sqrt{2} *32.88+15-3\sqrt{2}}{2} =\\= \frac{49- \sqrt{2} *(32.88+3)}{2} =\\= \frac{49- 35.88 \sqrt{2} }{2}[/tex]