Question

[3^2X3^3+2^54:2^52+(3^5)^4:3^20]:31=​

Answer 1

Răspuns:

(3^2+3 + 2^54-52 + 3^5×4 : 3^20) :31= (3^5 + 2^2 + 3^20 : 3^20) :31= (243+4+3^20-20):31= (247+3^0):31=(247+1):31=248:31=8