Question

[3^3*3+2^45/2^42+(3^5)^6/3^29+9^0]/31
Va rog ajutati-ma......Multumesc

Answer 1

(3^4 + 2^3 + 3^30 / 3^29 +1)/31 =
(3^4 + 2^3 + 3^1 +1) / 31=
(81+8+3+1)/31=
(89+3+1)/31=
(92+1)/31=
93/31 = 3