Question

3+3×{3+3×[3+3×(3-3÷a)]}=3x31. Cine face primul primeste coroana

Answer 1

3+3x{3+3x[3+3x(3-3:a)]}=3x31
3+3x{3+3x[3+3x(3-3:a)]}=93
3x{3+3x[3+3x(3-3:a)]}=93-3=90
3+3x[3+3x(3-3:a)]=90:3=30
3x[3+3x(3-3:a)]=30-3=27
3+3x(3-3:a)=27:3=9
3x(3-3:a)=9:3=3
3-3:a=3:3=1
3:a=3-1=2
a=3:2
a=1.5