Question

3+3x[333-(333:a-33+3)x3-(33-3)x3+3]-3x3=3 . care este rezolvarea?

Answer 1

Răspuns: a = 3

Explicație pas cu pas:

3 + 3 × [333 - (333 ÷ a - 33 + 3) × 3 - (33 - 3) × 3 + 3] - 3 × 3 = 3

3 + 3 × [333 - (333 ÷ a - 33 + 3) × 3 - 30 × 3 + 3] - 9 = 3

3 + 3 × [333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3] - 9 = 3

3 + 3 × [333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3] = 3 + 9

3 + 3 × [333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3] = 12

3 × [333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3] = 12 - 3

3 × [333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3] = 9

333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3 = 9 ÷ 3

333 - (333 ÷ a - 33 + 3) × 3 - 90 + 3 = 3

333 - (333 ÷ a - 33 + 3) × 3 - 90 = 3 - 3

333 - (333 ÷ a - 33 + 3) × 3 - 90 = 0

333 - (333 ÷ a - 33 + 3) × 3 = 0 + 90

333 - (333 ÷ a - 33 + 3) × 3 = 90

(333 ÷ a - 33 + 3) × 3 = 333 - 90

(333 ÷ a - 33 + 3) × 3 = 243

333 ÷ a - 33 + 3 = 243 ÷ 3

333 ÷ a - 33 + 3 = 81

333 ÷ a - 33 = 81 - 3

333 ÷ a - 33 = 78

333 ÷ a = 78 + 33

333 ÷ a = 111

a = 333 ÷ 111

a = 3

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Verificare: 3 + 3 × [333 - (333 ÷ 3 - 33 + 3) × 3 - (33 - 3) × 3 + 3] - 3 × 3 = 3

3 + 3 × [333 - (111 - 33 + 3) × 3 - 30 × 3 + 3] - 9 = 3

3 + 3 × [333 - (78 + 3) × 3 - 90 + 3] - 9 = 3

3 + 3 × (333 - 81 × 3 - 90 + 3) - 9 = 3

3 + 3 × (333 - 243 - 90 + 3) - 9 = 3

3 + 3 × (90 - 90 + 3) - 9 = 3

3 + 3 × (0 + 3) - 9 = 3

3 + 3 × 3 - 9 = 3

3 + 9 - 9 = 3

12 - 9 = 3

3 = 3 ✔