Question

[3/4+2/3:(3/4-1/2)]*6/41. b) [7/5:14/15+3/2:(9/4-1 întreg 1/2)]*2/7​

Answer 1

Răspuns:

Explicație pas cu pas:

a) [3/4+2/3:(3/4-1/2)]*6/41= [3/4+2/3:(3/4-2/4)]*6/41=(3/4+2/3:1/4)*6/41=(3/4+2/3*4/1)*6/41=(3/4+8/3)*6/41=(9/12+32/12)*6/41=41/12*6/41=1/2

b) [7/5:14/15+3/2:(9/4-1 întreg 1/2)]*2/7​=  [7/5:14/15+3/2:(9/4-1*2+1/2)]*2/7​=

[7/5:14/15+3/2:(9/4-3/2)]*2/7​=  [7/5:14/15+3/2:(9/4-6/4)]*2/7​= (7/5:14/15+3/2:3/4)*2/7=(7/5*15/14+3/2*4/3)*2/7=(3/2+2)*2/7= (3/2+4/2)*2/7=7/2*2/7=1