Question

(3^4+3^5+3^6+3^7):(2^5-2^4-2^3)vaul acela in jos este puterea

Answer 1

(3^4+3^5+3^6+3^7):(2^5-2^4-2^3)= 3⁴*(1+3+9+27) : 2³(4-2-1)=
=81*40 : 8*1=81*5= 405

Answer 2

=3^4+3^5+3^6+3^7=3^4(1+3+9+27)=3^4•40


2^5-2^4-2^3=2^3(4-2-1)=2^3=8


3^4•40:8=81•5=405