Question

√3(4+√6)-(√12- √18)+(√27+2√6):√3-(√8+3)=? Va rogggg ajutatimaaaa!!!!!!!!!!

Answer 1

$\displaystyle \sqrt{3} \left(4+ \sqrt{6} \right)-\left( \sqrt{12} - \sqrt{18} \right)+\left( \sqrt{27} +2 \sqrt{6} \right): \sqrt{3} -\left( \sqrt{8} +3\right)= \\ \\ =4 \sqrt{3} + \sqrt{18} - \sqrt{12} + \sqrt{18} + \sqrt{9} +2 \sqrt{2} - \sqrt{8} -3= \\ \\ =4 \sqrt{3} +3 \sqrt{2} -2 \sqrt{3} +3 \sqrt{2} +3+2 \sqrt{2} -2 \sqrt{2} -3=2 \sqrt{3} +6 \sqrt{2}$