Question

[(3^4)^6-(3^2)^11]^3•(2^4•3^33)^2=

Answer 1

[tex] [( 3^{4}) ^{6}-( 3^{2}) ^{11}]*( 2^{4}* 3^{33}) ^{2}=( 3^{24}- 3^{22}) ^{3}* 2^{8}* 3^{66} [/tex]$=(( 3^{2}-1)* 3^{22}) ^{3}* 2^{8} * 3^{66}= (( 9-1)* 3^{22}) ^{3}* 2^{8} * 3^{66}$$=(8*3^{22}) ^{3}* 2^{8} * 3^{66}=512* 3^{66}* 2^{8}* 3^{66}= 2^{9} * 3^{66}* 2^{8}* 3^{66}$$=2 ^{9+8}* 3^{66+66} = 2^{17}* 3^{132}$