Question

(3)‐⁴ - 7 pe 3 =
A.4
B.2
C.-2
D.0​

Answer 1

$\bf 3^{-4} -\dfrac{7}{3}=\dfrac{1}{3^{4}}-\dfrac{7}{3}=\dfrac{1}{81}}-\dfrac{7}{3}=$

$\bf \dfrac{1}{81}}-\dfrac{7\cdot27}{81}=\dfrac{1 - 189}{81}}=\boxed{\bf -\dfrac{188}{81}}}$ sau $\boxed{\bf-2\dfrac{26}{81}}$