Question

-3/41×20 intregi 1/2-8/3×(1 intreg-5/13:2/13)

Answer 1

20 intregi 1/2 = (20×2+1)/2 = 41/2

1 intreg 5/13 = (1 × 13 + 5)/13 = 18/13

-3/41 × 41/2 - 8/3 × (18/13 : 2/13) =

- 3/2 - 8/3 × (18/13 × 13/2) =

- 3/2 - 8/3 × 18/2 =

- 3/2 - 8/3 × 9 =

- 3/2 - 8 × 3 =

- 3/2 - 24 =

( - 3 - 24×2)/2 =

(- 3 - 48)/2 =

- 51/2