Question

[(-3/4la puterea 6)×(-3/4la puterea 8)]la puterea 4:(1-1/4):(1+1/2)​

Answer 1

...$\it \big[\Big(-\dfrac{3}{4}\Big)^6\ \cdot\Big(-\dfrac{3}{4}\Big)^8\Big]^4:(1-\dfrac{1}{4}):(1+\dfrac{1}{2})=\Big(-\dfrac{3}{4}\Big)^{14\cdot4}:\dfrac{3}{4}:\dfrac{3}{2}=\\ \\ \\ =\Big(\dfrac{3}{4}\Big)^{55}\cdot\dfrac{2}{3}=\dfrac{3^{55}}{2^{110}}\cdot\dfrac{2}{3}=\dfrac{3^{54}}{2^{109}}$

Answer 2

Răspuns:

Explicație pas cu pas:

[(-3/4la puterea 6)×(-3/4la puterea 8)]la puterea 4:(1-1/4):(1+1/2)​ =

(3/4 ^(6+8)) ^(4 : 3/4 : 3/2) =

(3/4 ^14) ^ 4*4/3 * 2/3) =

(3/4 ^14) ^32/9 =

3/4 ^(14*32/9) =

3/4 ^(448/9).

 Ar fi fost mult mai bine daca ai fi atasat o poza a enuntului.

Eu am rezolvat aici exact enuntul postat de tine, dar nu-mi place rezultatul obtinut.