Question

(3^5)^7:(3^2)^17-2^2+1^2009

Answer 1

$( {3}^{5} )^{7} \div {( {3}^{2}) }^{17} - {2}^{2} + 1^{2009} = \\ = {3}^{35} \div {3}^{34} - 4 + 1 \\ = 3 -4 + 1 \\ = 0$