Question

√3+√6(2supra √3 + 3 supra √2) -4√6(1 supra √3 + 1 supra √2)+√8=?

Answer 1

[tex] \sqrt{3} + \sqrt{6} ( \frac{2}{ \sqrt{3} } + \frac{3}{ \sqrt{2} } ) -4 \sqrt{6} ( \frac{1}{ \sqrt{3} } + \frac{1}{ \sqrt{2} } ) + \sqrt{8} = = \sqrt{3} + \frac{ 2 \sqrt{6} } { \sqrt{3} } + \frac{3 \sqrt{6} }{ \sqrt{2} } - \frac{4 \sqrt{6} }{ \sqrt{3} } - \frac{4 \sqrt{6} }{ \sqrt{2} } + \sqrt{8} = \sqrt{3} + 2 \sqrt{2} + 3 \sqrt{3} - 4 \sqrt{2} - 4 \sqrt{3} + 2 \sqrt{2} Se . reduce . totul . = 0 [/tex]