Question

(3/7)^11×(9/49)^3÷(3/7)^15 . calculati ​

Answer 1

${( \frac{3}{7} )}^{11} \times {( \frac{9}{49} )}^{3} \div {( \frac{3}{7} )}^{15}$

$= {( \frac{3}{7} )}^{11} \times {( \frac{ {3}^{2} }{ {7}^{2} }) }^{3} \div {( \frac{3}{7} )}^{15}$

$= {( \frac{3}{7}) }^{11} \times { [ {( \frac{3}{7} )}^{2} ]}^{3} \div {( \frac{3}{7} )}^{15}$

$= {( \frac{3}{7} )}^{11} \times {( \frac{3}{7}) }^{2 \times 3} \div {( \frac{3}{7} )}^{15}$

$= {( \frac{3}{7}) }^{11} \times {( \frac{3}{7} )}^{6} \div {( \frac{3}{7} )}^{15}$

$= {( \frac{3}{7} )}^{11 + 6 - 15} = {( \frac{3}{7}) }^{17 - 15}$

$={( \frac{3}{7} )}^{2} =\frac{{3}^{2}}{{7}^{2}}=\frac{9}{49}$